56x^2+296x-240=0

Solution for 56x^2+296x-240=0 equation:

56x^2+296x-240=0

a = 56; b = 296; c = -240;
Δ = b2-4ac
Δ = 2962-4·56·(-240)
Δ = 141376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{141376}=376$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(296)-376}{2*56}=\frac{-672}{112}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(296)+376}{2*56}=\frac{80}{112}
=5/7
$